Pluck assigned pages from A to B

Kirby 3 Solved ✅
1

My website contains pages for artists and pages for projects.
In the project page I can select children from the artists page, called artist.

  artist:
    type: pages
    query: site.children.template("artists").children

This is simple, because each project has at least 1 artist to select from.

Now what I want is to show the assigned projects in the artist page.
In the project page I just call $page->artist()->toPages();.

  <?php $artists = $page->artist()->toPages();
    foreach($artists as $artist): ?>
      <a href="<?= url($artist) ?>"><?= $artist->title() ?></a>
    <?php endforeach ?>

But how is it with the artist page?
I was thinking of filtering each project that has the name of the artist, but is there another, more efficient was of doing that?

2

No, that’s the way to go forward.

3

Hey first of all thank you :slight_smile:
I have another more advanced question.
I could just filter each page, but the pages field stores an array, because there can be more then one artist assigned to a project.
So I cant really use the filterBy('artists' $page->title(), ',')

Here is my suggested solution (We are in a artist page):

<?php
$title = $page->title(); #artist 01
$projects = $site->children()->template('projects')->children(); #project 01, project 02, etc.

foreach($projects as $page):

  foreach ($page->artist()->toPages() as $related):

    $artist_project = $related->title();

    if($artist_project == $title): #I thought to compare the current page title with the pages in project, that is probably not cool
    #What else can I do? I'm stuck.
    #After the if i want to echo the title and url of the correct project, where the artist is assigned to.

        echo $page->title();

    endif;

  endforeach;
  
endforeach ?>

It’s so simple in theory, but I just cant get over the conversion from the array to the correct name, and then compare each project->artist.

4

Quick question, what is stored in your pages field, usually that is not the title but the page id…

5

If I assign 2 artist in one project, it looks like that:

Artist:

- artists/artist-01
- artists/artist-02
6

This should work:

$projects = page('projects')->children()->listed();

$currentArtistProjects =  $projects->filter(function($project) use($page) {
  $artists = $project->artist()->toPages();
  if ($artists->has($page)) {
      return $project;
  }
});