Pages field Query using findBy('uuid')

Kirby 4 Question❓
1

Hey everyone,

Is it possible to show in Pages field only certain pages by their UUID ?
Doing for example:

fields:
    selection:
        type: pages
        label: Sélection des sous-pages de la page {{ page.title }}
        query: site.children.findBy('uuid', ['WWX33m8mf79j1CUW','Ky3tVOzt68TmfMs8','kaXOlp8JIPe5l8rD'])

The aim is not to use the page name because the user can change it:

query: site.children.find(['ressources','solutions','persona'])
2

Try filterBy and you have to pass the uuid with the schema page:/xxxxx

3

Hi Texnixe,

Do you mean?

query: site.children.filterBy('uuid', ['page:/WWX33m8mf79j1CUW','page:/Ky3tVOzt68TmfMs8','page:/kaXOlp8JIPe5l8rD'])

I tried but got “No pages to select” in the select dialog. Maybe sadly it’s not possible.

4

Almost, with an array you need to use in:

query: site.children.filterBy('uuid', 'in', ['page:/WWX33m8mf79j1CUW','page:/Ky3tVOzt68TmfMs8','page:/kaXOlp8JIPe5l8rD'])

Note that site.children only fetches first level pages.

5

Yes, that’s exactly what I just tried and it’s the right request.

We’re synchro!

Thanks!