Using images inside structure field

Kirby 2 Solved āœ…
1

Hi. For a project Iā€™m working on I needed to add an image inside a structure field, that will then be available to the template. I used the following code to do this, but for some reason I think my solution is not very elegant and could be simpler. Any ideas?

Blueprint

publications:
    label: Publications
    type: structure
    fields:
        name:
            label: Name
            type: text
        info:
            label: Info
            type: text
        preview:
            label: Preview
            type: select
            options: images    
    width: 1/2

Template

<?php $publications = yaml($page->publications()) ?>
<?php foreach($publications as $publication): ?>
    <div class="publication">
        <div class="name">
            <?php echo $publication['name'] ?><br />
        </div>
        <div class="info">
            <?php echo $publication['info'] ?>
        </div>
        <div class="preview">
            <?php $previewName = $publication['preview'] ?>
            <?php if ($previewName != ""): ?>
                <?php $previewUrl = $page->files()->find($previewName) ?>
                <?php echo $previewUrl->crop(400, 250) ?>
            <?php endif ?>
        </div>
    </div>
<?php endforeach ?>
2

Your code is perfectly alright. The only thing you could shorten is this line:

<?php $previewUrl = $page->files()->find($previewName) ?>

to

<?php $previewUrl = $page->file($previewName) ?>

Other than that, you could use the toStructure() method instead of the yaml() method.

3

Ah, good to know! Still your recommendations help as Iā€™m trying to keep code as clean as possible. Thanks.

4

Just on a side note, you can also use chaining syntax instead of the brackets (was introduced a while ago and makes the code more coherent:

<?php $publications = $page->publications()->yaml() ?>
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