Undefined variable when passing variable to snippet

Kirby 2 Solved ✅
1

Howdy!

Trying to split my code while it keeps growing and thought I was doing almost exactly what this example is doing
https://getkirby.com/docs/templates/snippets

The Template

$items = page('home’)
          ->children()
          ->visible()
          ->filterBy(‘tag’, 'services', ',');

?>

<?php foreach ($items as $item): ?>

    <?php if ($item->share() != '1'): ?>
        <?php snippet(’share-component’, array(‘share-component’ => $item)) ?>
    <?php else: ?>
        …something else
    <?php endif ?>

<?php endforeach ?>

The Snippet (share-component)

 <a href="http://www.facebook.com/sharer.php?u=<?=rawurlencode($item->url());?>" target="blank" title="Share on Facebook"
    …svg icon
</a>

Unfortunately this gives me error message that says the variable ($item) is undefined.

Could someone kindly tell me what I’m doing wrong here?

2

You are passing the variable $item to share-component. But the variable you use in your snippet is not called $share-component but $item.

Correct code:

<?php snippet('share-component', ['item' => $item]) ?>

The key in the array is the name of the variable you use in your snippet, the value is the variable that you pass to the snippet.

3

So that was the problem.

Thank you so much for your help!