Receiving an undefined variable error when filter isn't used in URL

Kirby 3 Solved ✅
1

Hi there, I’m trying to follow along with Filtering via routes from the Cookbook, slightly modified to filter the contents of a Structure field using multi-word parameters.

On the page itself, I include the following PHP:

<?php
    $publications = $page->publications()->toStructure();

    if($pubtype) {
        $pubtype = urldecode($pubtype);
        $publications = $publications->filterBy('pubtype', $pubtype, ',');
    }
?>

and in config.php I have:


'routes' => [
        [
            'pattern' => 'publications/(:any)',
            'action' => function ($pubtype) {
                if ($page = page('publications/' . $pubtype)) {
                    return $page;
                } else {
                    urlencode($pubtype);
                    return page('publications')->render([
                        'pubtype' => $pubtype
                    ]);
                }
            }
        ]
    ]

When I enter a URL that includes a parameter (e.g. http://example.com/publications/Example+One), the page loads and the filter works as intended. However, without the parameter in the URL (http://example.com/publications), I land on the Kirby CMS Debugger screen with the error “Undefined variable $pubtype”

Thanks in advance for any help with this!

2

As the error says, in that case your variable is not defined. So instead of

    if($pubtype) {

which does not check if the variable exists but if it is not equal null or false, use

if (isset($pubtype)) {
  // do stuff
}
1 Like
3

Great, thanks!