Filtering pages by template and `slug`

Kirby 2 Solved ✅
1

I am working on a multi-language website and have to manually build url() for some links.

I tried to use this syntax to build the first part of the URL

$site->index()->filterBy('template', 'template-name')

but the result I get is null.

I realised it is because what I get is a collection of pages, but is it possible to only extract its uri or slug?

2

A collection does not have a URL, what exactly are you trying to do?

3

UPDATE, found a simple solution even though it is semantically hacky? I just added ->first() as the collection with that template only has one page and several subpages.

$places = $site->children()->filterBy('template', 'places')->first();

<a href="<?php echo $places->url() . '/' . str::slug($page->location()->html()) ?>">

In this way also the url is automatically translated into the two languages.

1 Like
4

BTW: findBy() returns a single page.

$places = $site->children()->findBy('template', 'places');
1 Like
5

Great! Even better, I thought that should have been an easier simpler command.