Just get page name in the url?

Kirby 2 Solved ✅
1

How do I get the /page-name only ? And just check if it´s true?

I want to check if it´s true. My code isn´t working as is.

<?php if(!$children->parent() == 'page-name'): ?>
// do something
<?php endif ?>

Or maybe there is a better way? I want to show menu and submenu but hide the children from one specific page. Is there a better way?

2

Here is my full menu for the time:

<? foreach ($pages->visible() as $item): ?>

          <li class="<?= $item->isOpen() ? "active" : "" ?>">
            <a class="bold-menu" href="<?php echo $item->url() ?>"><?php echo $item->title()->html() ?>
            </a>
          </li>

            <?php
            // get all children for the current menu item
            $children = $item->children()->visible();
            // display the submenu if children are available
            if($children->count() > 0):
            ?>
              <?php foreach($children as $child): ?>
              <li><a class="<?php e($child->isOpen(), 'active') ?> sub-menu" href="<?php echo $child->url() ?>"><?php echo $child->title()->html() ?></a></li>
              <?php endforeach ?>
            <?php endif ?>

          <? endforeach ?>
3

Found this solution: